How do you solve $8 ^(2x) — 5 = 48$ ?

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Answer 1 · 2018-03-23T17:06:26

$x=log_8(53)/2~~0.95465$

$8 ^(2x) - 5 = 48|+5$
$8 ^(2x) = 53|log_8()$
$2x=log_8(53)|:2$
$x=log_8(53)/2~~0.95465340909$

How do you solve 8 ^(2x) — 5 = 488 ^(2x) — 5 = 48?