How do you solve $\frac{8}{n} = \frac{3}{n - 5}$ $8/n=3/(n-5)$ ?

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Answer 1 · 2017-01-18T19:43:37

$n = 8$ $n = 8$

Given:

$\frac{8}{n} = \frac{3}{n - 5}$ $8/n = 3/(n-5)$

Multiply both sides by $n (n - 5)$ $n(n-5)$ to get:

$8 (n - 5) = 3 n$ $8(n-5) = 3n$

That is:

$8 n - 40 = 3 n$ $8n-40 = 3n$

Add $40 - 3 n$ $40-3n$ to both sides to get:

$5 n = 40$ $5n = 40$

Divide both sides by $5$ $5$ to find:

$n = 8$ $n = 8$

How do you solve 8n=3n−58/n=3/(n-5)?