How do you solve $9^(8x)=13^(-x+7)$ ?

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Answer 1 · 2016-02-27T23:36:49

$x=7-8log(9)/log(13)$

$9^(8x)=13^(-x+7)$

You need to use logarithms:

$8x. log(9)=(-x+7)log(13)$

$8log(9)/log(13)=-x+7$

$x=7-8log(9)/log(13)$

It is a very ugly solution.

How do you solve 9^(8x)=13^(-x+7)9^(8x)=13^(-x+7)?