How do you solve $9/(b+5)=3/(b-3)$ ?

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Answer 1 · 2016-11-27T23:19:40

$b=7$

$frac{9}{b+5}=frac{3}{b-3}$

Cross multiply:
$9(b-3)=3(b+5)$

Distribute:
$9b-27=3b+15$

Solve for b:
$6b=42$

$b=7$

*Make sure the answer works in the original function, and make sure you don't divide by zero.

How do you solve 9/(b+5)=3/(b-3)9/(b+5)=3/(b-3)?