How do you solve $9^(x-1)=3^x$ ?

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Answer 1 · 2015-04-29T19:15:30

$x=2$

Solution

$9^(x-1)=3^x$

Making bases of both sides equal

As 9 can be written as $9=3^2$

$3^(2(x-1))=3^x$

It must be equal to

$2(x-1)=x$

$2x-2=x$

$2x-x=2$

$x=2$

How do you solve 9^(x-1)=3^x9^(x-1)=3^x?