Question

How do you solve `9e^(5x) = 1269`?

Answer 1

I found: `x=0.98975`

Explanation:

I would rearrange it to get:
`e^(5x)=1269/9`
`e^(5x)=141`
take the natural log on both sides:
`ln(e^(5x))=ln(141)`
and get:
`cancel(ln)(cancel(e)^(5x))=ln(141)`
`5x=ln(141)`
`x=ln(141)/5=0.98975`