Question

How do you solve `9tan^2x-3=0`?

Answer 1

`x in {pi/6+kpi,(5pi)/6+kpi}, AAkinZZ`

Explanation:

`9tan^2(x)-3=0`

`rarr 9tan^2(x)=3`

`rarr tan^2(x)=1/3`

`rarr tan(x)=+-1/sqrt(3)`

This is one of the standard reference angles: `pi/6 or 30^@`

Note the image below is (obviously) inaccurate.
Furthermore, I've used the `30^@` notation instead of `pi/6` because it was easier and faster to enter using my Paint program