How do you solve $\frac{a}{a + 3} + \frac{a^{2}}{a + 3} = 2$ $a/(a+3)+a^2/(a+3)=2$ ?

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Answer 1 · 2018-06-04T11:48:31

$a = - 2 or a = 3$ $a=-2 or a=3$

$\frac{a}{a + 3} + \frac{a^{2}}{a + 3}$ $a/(a+3)+a^2/(a+3)$

$:.(a+a^2=2(a+3))/(a+3)$

multiply both sides by $a+3$

$:.a+a^2=2a+6$

$:.a^2+a-2a-6=0$

$:.a^2-a-6=0$

$:.=(a+2)(a-3)$

$:.a=-2 or a=3$

How do you solve a/(a+3)+a^2/(a+3)=2aa+3+a2a+3=2a/(a+3)+a^2/(a+3)=2?