Question

How do you solve a triangle if you are given a=162 b=185 and c=323?

Answer 1

Use the cos law: a^2 = b^2 + c^2 - 2bc.cos A

`cos A = (b^2 + c^2 - a^2)/(2bc) =`(112,310)/(119,510) = 0.94 ->
-> A = 19.95 deg

`sin B = (b.sin A)/a = (185.(0.34))/162`= 0.39 -> B = 22.85 deg

C = 180 - A - B = 180 - 19.95 - 22.85 = 137.20