How do you solve $arctan (2 x) = - 1$ $arctan(2x)= -1$ ?

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Answer 1 · 2016-07-10T16:09:08

$x = - \frac{1}{2} r a d i a n$ $x=-1/2 radian$ , assuming that angular measure is in radian unit.

So, $tan (2 x) = tan (- 1)$ $tan (2x)=tan(-1)$ , and so,

the principal value of 2x = -1 radian

$x = - \frac{1}{2}$ $x=-1/2$ radian .

For the general value, $2 x = n π - 1$ $2x = npi-1$ and

$x = (npi-1)/2 radians, n=0, +-1, +-2, +-3, ...$

1 radian = $(180/(pi)) ^o=57.3^o$ , nearly.

Answer 2 · 2016-07-10T22:55:46

$28^@66$

arctan 2x = -1
$2x = -1 rad. = 180^@/(3.14) = 57^@32$
$x = 28^@66$

How do you solve arctan(2x)= -1arctan(2x)=−1arctan(2x)= -1?