Question

How do you solve by clearing the denominator of `3/x+2/x^2=4`?

Answer 1

You may choose `x^2` as your common denominator (considering that has to be `x!=0` to avoid a division by zero). You get:
`(3*x)/(x)^2+2/x^2=(4x^2)/(x)^2`

Nultiplying both sides by `x^2`:
`3x+2=4x^2`
`4x^2-3x-2=0`

Which is a second degree equation.