How do you solve by substitution $2x-y=32$ and $y-5x=13$ ?

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Answer 1 · 2015-07-01T08:11:34

$color(blue)(x=-15, y=-62$

$2x-y=32$ .........equation $(1)$

$y-5x=13$
$color(blue)(y=13 + 5x$ ........equation $(2)$

Substituting equation $2$ in $1$ to find $x$ :

$2x-y=32$

$2x-color(blue)((13 + 5x))=32$

$-3x=32 +13$

$-3x=45$

$color(blue)(x=-15$

Finding $y$ from equation $2$
$y=13 +5x$

$y=13 -75$

$color(blue)(y = -62$
The solution for the equation is:
$color(blue)(x=-15, y=-62$

How do you solve by substitution 2x-y=322x-y=32 and y-5x=13y-5x=13?