How do you solve by substitution $- x + y = 5$ $-x+y=5$ and $y = - 3 x + 1$ $y=-3x+1$ ?

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How do you solve by substitution $- x + y = 5$ $-x+y=5$ and $y = - 3 x + 1$ $y=-3x+1$ ?

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Answer 1 · 2015-06-06T23:08:11

[1] $XXXX$ $color(white)("XXXX")$ $- x + y = 5$ $-x+y =5$
[2] $XXXX$ $color(white)("XXXX")$ y = -3x+1

Using [2] substitute $(- 3 x + 1)$ $(-3x+1)$ for $y$ $y$ in [1]
[3] $XXXX$ $color(white)("XXXX")$ $- x + (- 3 x + 1) = 5$ $-x+(-3x+1) = 5$
Simplifying
[4] $XXXX$ $color(white)("XXXX")$ $- 4 x = 4$ $-4x = 4$
[5] $XXXX$ $color(white)("XXXX")$ $x = - 1$ $x = -1$

Using [5] substitute $(- 1)$ $(-1)$ of $x$ $x$ in [1]
[6] $XXXX$ $color(white)("XXXX")$ $- (- 1) + y = 5$ $-(-1) + y = 5$
Simplifying
[7] $XXXX$ $color(white)("XXXX")$ $y = 4$ $y=4$

Solution is $(x, y) = (- 1, 4)$ $(x,y) = (-1,4)$

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How do you solve by substitution $- x + y = 5$ $-x+y=5$ and $y = - 3 x + 1$ $y=-3x+1$ ?

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How do you solve by substitution -x+y=5−x+y=5-x+y=5 and y=-3x+1y=−3x+1y=-3x+1?

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How do you solve by substitution $- x + y = 5$ $-x+y=5$ and $y = - 3 x + 1$ $y=-3x+1$ ?