Question

How do you solve `cosx-1=-cosx`?

Answer 1

The solutions are `S={pi/3+2kpi, 5/3pi+2kpi}`, `AA k in ZZ`

Explanation:

The equation is

`cosx-1=-cosx`

`=>`, `2cosx=1`

`=>`, `cosx=1/2`

The solutions are

`{(x=pi/3+2kpi),(x=5/3pi+2kpi):}`, `AA k in ZZ`