How do you solve $cot x = cos x$ $cotx=cosx$ in the interval $0 \leq x \leq 2 π$ $0<=x<=2pi$ ?

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Answer 1 · 2018-03-17T11:28:07

Solution: In interval, $0 \leq x \leq 2 π; x = \frac{π}{2}$ $0<=x <= 2pi ; x= pi/2$

$cot x = cos x or \frac{cos x}{sin x} = cos x or sin x = \frac{cos x}{cos x}$ $cotx =cosx or cosx/sinx=cosx or sinx=cosx/cosx$ or

$sinx=1 ; sin (pi/2) =1 :. x= pi/2$

Solution: In interval $0<=x <= 2pi ; x= pi/2$ [Ans]

How do you solve cotx=cosxcotx=cosxcotx=cosx in the interval 0<=x<=2pi0≤x≤2π0<=x<=2pi?