How do you solve e^(12-5x) -7 = 123? Precalculus Solving Exponential and Logarithmic Equations Logarithmic Models 1 Answer Sudip Sinha Jul 30, 2015 x = 1/5 (12 - ln(130)) Explanation: e^(12−5x)−7 = 123 => e^(12−5x) = 123 + 7 = 130 (Add 7 to both sides) => 12−5x = ln(130) (Take natural logarithm on both sides) => −5x = -12 + ln(130) (Add -12 to both sides) => 5x = 12 - ln(130) (Multiply by -1) => x = 1/5 (12 - ln(130)) (Divide by 5 on both sides) If you need, you may use a calculator to get log(130) = 4.8675 . Put this value to get x = 1.4265 . Answer link Related questions What is a logarithmic model? How do I use a logarithmic model to solve applications? What is the advantage of a logarithmic model? How does the Richter scale measure magnitude? What is the range of the Richter scale? How do you solve 9^(x-4)=81? How do you solve logx+log(x+15)=2? How do you solve the equation 2 log4(x + 7)-log4(16) = 2? How do you solve 2 log x^4 = 16? How do you solve 2+log_3(2x+5)-log_3x=4? See all questions in Logarithmic Models Impact of this question 2997 views around the world You can reuse this answer Creative Commons License