How do you solve $e^{4 x - 6} - 8 = 11212$ $e^(4x - 6) - 8 = 11212$ ?

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Answer 1 · 2016-02-07T20:25:36

$x = ln (\sqrt[4]{11220 e^{6}})$ $x=ln(root(4)(11220e^6))$

$e^{4 x - 6} - 8 = 11212$ $e^(4x-6)-8=11212$

$e^{4 x - 6} = 11220$ $e^(4x-6)=11220$

$4 x - 6 = ln (11220)$ $4x-6=ln(11220)$

$4 x = ln (11220) + 6$ $4x=ln(11220)+6$

$x = \frac{ln (11220) + 6}{4}$ $x=(ln(11220)+6)/4$

How do you solve e^(4x - 6) - 8 = 11212e4x−6−8=11212e^(4x - 6) - 8 = 11212?