How do you solve $e^(ln(sinx))=1$ in the interval [0,360]?

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Answer 1 · 2016-11-05T03:12:14

$x= 90˚$ .

Take the natural logarithm of both sides.

$ln(e^(ln(sinx))) = ln1$

Simplify using the rule $lna^n = nlna$ .

$ln(sinx)(lne) = 0$

Apply the identity $ln(e) = 1$ .

$ln(sinx) = 0$

$sinx = e^0$

$sinx = 1$

$x = 90˚$

Hopefully this helps!

How do you solve e^(ln(sinx))=1e^(ln(sinx))=1 in the interval [0,360]?