How do you solve $e^{x} - 1 - 5 = 5$ $e^x − 1 − 5 = 5$ ?

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Answer 1 · 2015-12-25T15:40:02

$x = ln 11$ $x=ln11$

$e^{x} - 1 - 5 = 5$ $e^x-1-5=5$

$thereforee^x=5+5+1=11$

$therefore lne^x=ln11$

$therefore xlne=ln11$

$therefore x=ln11$

How do you solve e^x − 1 − 5 = 5 ex−1−5=5e^x − 1 − 5 = 5 ?