How do you solve each system of equations and then check the answer algebraically? 11) -6x+3y=33 -4x+y=16 12)2y=5x-1 x+y=-1

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How do you solve each system of equations and then check the answer algebraically? 11) -6x+3y=33 -4x+y=16 12)2y=5x-1 x+y=-1

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Answer 1 · 2018-01-11T14:16:36

$see explanation$ $"see explanation"$

Explanation:

$(11)$ $(11)$

$- 6 x + 3 y = 33 \to (1)$ $-6x+3y=33to(1)$

$- 4 x + y = 16 \to (2)$ $-4x+y=16to(2)$

$from (2) x y = 16 + 4 x \to (3)$ $"from "(2)color(white)(x)y=16+4xto(3)$

$Substitute y = 16 + 4 x in equation (1)$ $color(blue)"Substitute "y=16+4x" in equation "(1)$

$- 6 x + 3 (16 + 4 x) = 33$ $-6x+3(16+4x)=33$

$\Rightarrow - 6 x + 48 + 12 x = 33$ $rArr-6x+48+12x=33$

$\Rightarrow 6 x + 48 = 33$ $rArr6x+48=33$

$subtract 48 from both sides$ $"subtract 48 from both sides"$

$6xcancel(+48)cancel(-48)=33-48$

$rArr6x=-15$

$"divide both sides by 6"$

$(cancel(6) x)/cancel(6)=(-15)/6$

$rArrx=-15/6=-5/2$

$"substitute this value in equation "(3)$

$rArry=16+(4xx-5/2)=16-10=6$

$rArr(x,y)to(-5/2,6)$

$color(blue)"As a check"$

$"substitute the solution into either of the 2 equations"$

$(2)to(-4xx-5/2)+6=10+6=16larr" True"$

$"this confirms that "(-5/2,6)" is the solution"$

$(12)$

$"the solution is "(x,y)to(-1/7,-6/7)$

$"this is done in exactly the same way as 11"$

$"you may wish to try it for yourself"$

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How do you solve each system of equations and then check the answer algebraically? 11) -6x+3y=33 -4x+y=16 12)2y=5x-1 x+y=-1

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