How do you solve for Kc in $7.2647 = -ln(Kc)$ ?

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Answer 1 · 2016-03-30T13:26:46

$K_c=e^(-7.2647)=0.0007$

$7.2647=-ln(K_c)$

$therefore ln(K_c)=-7.2647$

$thereforee^(ln(K_c))=e^(-7.2647)$

$therefore K_c=e^(-7.2647)=0.0007$ .

How do you solve for Kc in 7.2647 = -ln(Kc) 7.2647 = -ln(Kc) ?