How do you solve for m in $\frac{m}{6} = \frac{1}{3}$ $m/6 = 1/3$ ?

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Answer 1 · 2015-04-07T12:00:10

In general if
$a = b$ $a=b$
then
$k \cdot a = k \cdot b$ $k*a = k*b$

That means we can multiply both sides of an equation by a constant and the equation will still be true.

Multiply both sides of $\frac{m}{6} = \frac{1}{3}$ $m/6 = 1/3$ by $6$ $6$
$cancel(6)*m/cancel(6) = 6*1/3 = 2$

$m = 2$

How do you solve for m in m/6 = 1/3m6=13m/6 = 1/3?