How do you solve for x in $(125)^x = 625$ ?

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Answer 1 · 2016-04-09T05:49:27

$x=4/3=1.333$

$125^x=625$ means $x=log_(125)625$

As $log_ba=loga/logb$

$x=log625/log125=2.79588/2.09691=1.333$

Alternately - $125^x=625hArr(5^3)^x=5^4hArr5^(3x)=5^4$ or

$3xlog5=4log5$ or $x=4/3=1.333$

How do you solve for x in (125)^x = 625(125)^x = 625?