How do you solve for x in 2^ logx = 1/42logx=14? Precalculus Solving Exponential and Logarithmic Equations Logarithmic Models 1 Answer Alan P. Dec 22, 2015 x=0.01x=0.01 Explanation: Note that color(white)("XXX")1/4=1/(2^2)=2^(-2)XXX14=122=2−2 So if 2^(log(x)) = 1/42log(x)=14 then color(white)("XXX")log(x)=-2XXXlog(x)=−2 color(white)("XXX")10^(-2) = xXXX10−2=x (based on definition of log) color(white)("XXX")x=1/100 = 0.01XXXx=1100=0.01 Answer link Related questions What is a logarithmic model? How do I use a logarithmic model to solve applications? What is the advantage of a logarithmic model? How does the Richter scale measure magnitude? What is the range of the Richter scale? How do you solve 9^(x-4)=819x−4=81? How do you solve logx+log(x+15)=2logx+log(x+15)=2? How do you solve the equation 2 log4(x + 7)-log4(16) = 22log4(x+7)−log4(16)=2? How do you solve 2 log x^4 = 162logx4=16? How do you solve 2+log_3(2x+5)-log_3x=42+log3(2x+5)−log3x=4? See all questions in Logarithmic Models Impact of this question 1316 views around the world You can reuse this answer Creative Commons License