How do you solve for x in 2^ logx = 1/42logx=14?

1 Answer
Dec 22, 2015

x=0.01x=0.01

Explanation:

Note that
color(white)("XXX")1/4=1/(2^2)=2^(-2)XXX14=122=22

So if 2^(log(x)) = 1/42log(x)=14
then
color(white)("XXX")log(x)=-2XXXlog(x)=2

color(white)("XXX")10^(-2) = xXXX102=x (based on definition of log)

color(white)("XXX")x=1/100 = 0.01XXXx=1100=0.01