How do you solve for x in 3^(2x) + 3^(x+1) - 4 = 0? Precalculus Solving Exponential and Logarithmic Equations Logarithmic Models 1 Answer kamil9234 Apr 26, 2018 x=0 Explanation: 3^(2x)+3^(x+1)=4 3^(2x)+3^(x+1)=1+3 3^(2x)+3^(x+1)=3^0+3^1 So: 2x=0 nn x+1=1 So: x=0 Answer link Related questions What is a logarithmic model? How do I use a logarithmic model to solve applications? What is the advantage of a logarithmic model? How does the Richter scale measure magnitude? What is the range of the Richter scale? How do you solve 9^(x-4)=81? How do you solve logx+log(x+15)=2? How do you solve the equation 2 log4(x + 7)-log4(16) = 2? How do you solve 2 log x^4 = 16? How do you solve 2+log_3(2x+5)-log_3x=4? See all questions in Logarithmic Models Impact of this question 6872 views around the world You can reuse this answer Creative Commons License