How do you solve for x in $9=2^(.84x)$ ?

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Answer 1 · 2015-12-05T15:38:25

$x~~3.77$ to 2 decimal places

Suppose we had $log(x^3)$

This is $log(x xx x xx x )$

Which is $log(x)+log(x)+log(x)$

Which is $3log(x)$
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
Given: $9=2^(0.84x)$

Take logs of both sides

$log(9) = 0.84xlog(2)$

$x=(log(9))/(0.84xxlog(2))$

$x~~3.77$ to 2 decimal places

How do you solve for x in 9=2^(.84x)9=2^(.84x)?