How do you solve for x in $y=(0.8)(0.84)^x$ ?

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Answer 1 · 2016-04-21T18:48:50

$x=(ln(y/0.8))/ln(0.84)$

$y/0.8 =(0.84)^x$

$ln(y/0.8)=ln(0.84)^x$

$ln(y/0.8)=x ln(0.84)$

$(ln(y/0.8))/ln(0.84) =x$

How do you solve for x in y=(0.8)(0.84)^xy=(0.8)(0.84)^x?