How do you solve for y in $3 x + 2 y = 12$ $3x+2y= 12$ ?

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Answer 1 · 2015-04-07T05:22:54

The answer is $y = - \frac{3}{2} x + 6$ $y=-3/2x+6$ .

$3 x + 2 y = 12$ $3x+2y=12$

Subtract 3x from both sides.

$2 y = 12 - 3 x$ $2y=12-3x$

Divide both sides by 2.

$(cancel(2)y)/(cancel(2))=(12)/(2)-(3)/(2)x$ =

$y=6-3/2x$

$y=-3/2x+6$

If this is meant to be the equation for a line in slope-intercept form, $-3/2$ is the slope, and $6$ is the y-intercept.

How do you solve for y in 3x+2y= 123x+2y=123x+2y= 12?