How do you solve for y in $3 x = 2 y - 18$ $3x = 2y - 18$ ?

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Answer 1 · 2015-10-17T01:02:05

3x = 2y - 18

-2y = -3x - 18

[-2y = -3x - 18]-1

2y = 3x + 18

$2 \frac{y}{2}$ $2y/2$ = $3 \frac{x}{2}$ $3x/2$ + $\frac{18}{2}$ $18/2$

$y = 3 \frac{x}{2} + 9$ $y = 3x/2 + 9$

How do you solve for y in 3x=2y−183x = 2y - 18?