How do you solve for y in $- 3 x + 5 y = - 10$ $-3x+5y=-10$ ?

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Answer 1 · 2015-04-11T09:36:31

$- 3 x + 5 y = - 10$ $-3x+5y=-10$

As we need to solve for $y$ $y$ , we transpose $- 3 x$ $-3x$ to the right hand side to get

$5 y = - 10 + 3 x$ $5y=-10 + 3x$

We divide both sides by 5

$(cancel(5)y)/cancel(5)=(-10 + 3x)/5$

$y = - 10/ 5 + (3x)/5$

$y = - 2 + (3x)/5$

$color(green)(y = (3x)/5 - 2$

How do you solve for y in -3x+5y=-10−3x+5y=−10-3x+5y=-10?