How do you solve $ln e^(-2x) = 8$ ?

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Answer 1 · 2016-02-19T11:34:12

I found: $x=-4$

We can first take the $-2x$ and place it in front of the log:

$-2xlne=8$

then remember that: $lne=1$
and write:

$-2x=8$
so that $x=-8/2=-4$

How do you solve ln e^(-2x) = 8ln e^(-2x) = 8?