How do you solve $ln (6 x - 5) = 3$ $ln(6x-5)=3$ ?

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Answer 1 · 2016-09-06T12:55:18

$x = 4.1809$ $x=4.1809$

As $ln (6 x - 5) = 3$ $ln(6x-5)=3$

$6 x - 5 = e^{3}$ $6x-5=e^3$

or $6 x = e^{3} + 5$ $6x=e^3+5$

i.e $x = \frac{e^{3} + 5}{6} = \frac{20.0855 + 5}{6} = \frac{25.0855}{6} = 4.1809$ $x=(e^3+5)/6=(20.0855+5)/6=25.0855/6=4.1809$

How do you solve ln(6x-5)=3ln(6x−5)=3ln(6x-5)=3?