How do you solve ln(x+1)−1=ln(x−1)? Precalculus Solving Exponential and Logarithmic Equations Logarithmic Models 1 Answer Alan P. Feb 24, 2016 x=e+1e−1 Explanation: Given XXXln(x+1)−1=ln(x−1) ⇒ XXXln(x+1)−ln(x−1)=1=ln(e) XXXln(x+1x−1)=ln(e) XXXx+1x−1=e XXXx+1=ex−e XXXx−ex=−e−1 XXXx(1−e)=−e−1 XXXx=e+1e−1≈2.164 Answer link Related questions What is a logarithmic model? How do I use a logarithmic model to solve applications? What is the advantage of a logarithmic model? How does the Richter scale measure magnitude? What is the range of the Richter scale? How do you solve 9x−4=81? How do you solve logx+log(x+15)=2? How do you solve the equation 2log4(x+7)−log4(16)=2? How do you solve 2logx4=16? How do you solve 2+log3(2x+5)−log3x=4? See all questions in Logarithmic Models Impact of this question 1372 views around the world You can reuse this answer Creative Commons License