How do you solve $ln x = 2$ $ln x=2$ ?

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How do you solve $ln x = 2$ $ln x=2$ ?

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Answer 1 · 2015-09-11T21:29:14

$x = e^{2}$ $x=e^2$

Explanation:

By definition of logarithms,
$y = {log}_{a} x \Leftrightarrow a^{y} = x$ $y=log_ax iff a^y=x$
Now ln is the natural logarithm and has base e, where $e \approx 2, 71828$ $e~~2,71828$
$therefore lnx=2=>log_ex=2$
$thereforex=e^2$

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How do you solve $ln x = 2$ $ln x=2$ ?

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