How do you solve $ln (x^{2}) = 16$ $ln(x^2)=16$ ?

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Answer 1 · 2016-01-29T16:55:53

I found: $x = e^{8} = 2, 980.95$ $x=e^8=2,980.95$

We can use the property of the logs that allows you to take out the exponent of the argument and place it as multiplier in front of the log to get:

$2 ln (x) = 16$ $2ln(x)=16$

rearrange:

$ln (x) = \frac{16}{2} = 8$ $ln(x)=16/2=8$

use the definition of log to get:

$x = e^{8} = 2, 980.95$ $x=e^8=2,980.95$

How do you solve ln(x2)=16ln(x^2)=16?