How do you solve ln x^3 = 2 ln 5 - 3 ln 2? Precalculus Solving Exponential and Logarithmic Equations Logarithmic Models 1 Answer Bdub Apr 21, 2016 x=root3(25/8)=root3 25 / 2 Explanation: lnx^3-2ln5+3ln2=0 lnx^3-ln5^2+ln2^3=0 lnx^3-ln25+ln8=0 ln((8x^3)/25)=0 e^0=(8x^3)/25 1=(8x^3)/25 25=8x^3 25/8=x^3 x=root3(25/8)=root3 25 / 2 Answer link Related questions What is a logarithmic model? How do I use a logarithmic model to solve applications? What is the advantage of a logarithmic model? How does the Richter scale measure magnitude? What is the range of the Richter scale? How do you solve 9^(x-4)=81? How do you solve logx+log(x+15)=2? How do you solve the equation 2 log4(x + 7)-log4(16) = 2? How do you solve 2 log x^4 = 16? How do you solve 2+log_3(2x+5)-log_3x=4? See all questions in Logarithmic Models Impact of this question 2007 views around the world You can reuse this answer Creative Commons License