How do you solve ln x^3 = 2 ln 5 - 3 ln 2?

1 Answer
Apr 21, 2016

x=root3(25/8)=root3 25 / 2

Explanation:

lnx^3-2ln5+3ln2=0
lnx^3-ln5^2+ln2^3=0
lnx^3-ln25+ln8=0
ln((8x^3)/25)=0
e^0=(8x^3)/25

1=(8x^3)/25

25=8x^3

25/8=x^3

x=root3(25/8)=root3 25 / 2