How do you solve $ln x - ln (x-3) = ln 5?$ ?

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Answer 1 · 2015-07-08T03:05:38

use of logarithm property and then antilog

remember

$lna-lnb=ln(a/b)$

so applying it here we see that

$lnx-ln(x-3)=ln5$ can be rewritten as

$ln(x/(x-3))=ln5$

now taking antilog on both sides we get

$antiln(ln(x/(x-3)))=antiln(ln5)$

$x/(x-3)=5$

solving the equation reveals

$x=15/4$

please feel free to comment if you find any mistake
Cheerio!

How do you solve ln x - ln (x-3) = ln 5?ln x - ln (x-3) = ln 5??