How do you solve ln(y-1) - ln(2) = x + ln x?

1 Answer
BeeFree
Dec 12, 2015

Use property of logs ...

Explanation:

ln[(y-1)/(2xxx)]=x

Exponentiate ...

e^{ln[(y-1)/(2xxx)]}=e^x

Simplify ...

(y-1)/(2x)=e^x

y=(2x)e^x+1

This function approaches y=1 as xrarr-oo. It never crosses the x-axis.

Hope that helps

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