How do you solve $ln y = 2 x + 4$ $ln y = 2x + 4$ ?

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Answer 1 · 2018-03-04T10:32:54

$y = e^{2 x + 4}$ $y=e^(2x+4)$

Assuming the goal is to isolate $y$ $y$ , we can do so by raising both sides as a power of $e$ $e$ , cancelling the natural logarithm:

$e^{ln (y)} = e^{2 x + 4}$ $e^ln(y)=e^(2x+4)$

$y = e^{2 x + 4}$ $y=e^(2x+4)$

How do you solve ln y = 2x + 4lny=2x+4ln y = 2x + 4?