How do you solve $ln 6 x + ln 2 x = ln 13$ $ln6x +ln2x = ln13$ ?

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How do you solve $ln 6 x + ln 2 x = ln 13$ $ln6x +ln2x = ln13$ ?

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Answer 1 · 2016-04-13T05:09:34

$x = \sqrt{\frac{13}{12}} = 1.041$ $x=sqrt(13/12)=1.041$ , nearly.

Explanation:

$ln a + ln b = ln a b$ $ln a+ln b = ln ab$
So, $ln (6 x) (2 x)) = ln (12 x^{2}) = ln 13$ $ln(6x)(2x))=ln(12x^2)=ln 13$
So, $12 x^{2} = 13$ $12x^2=13$
$x^{2} = \frac{13}{12}$ $x^2=13/12$
$x = \pm \sqrt{\frac{13}{12}}$ $x=+-sqrt(13/12)$
For the given form, negative solution is inadmissible.

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How do you solve $ln 6 x + ln 2 x = ln 13$ $ln6x +ln2x = ln13$ ?

1 Answer

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How do you solve ln6x +ln2x = ln13 ln6x+ln2x=ln13ln6x +ln2x = ln13 ?

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Explanation:

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How do you solve $ln 6 x + ln 2 x = ln 13$ $ln6x +ln2x = ln13$ ?