How do you solve $ln x = 2$ $lnx=2$ ?

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Answer 1 · 2018-05-28T03:23:44

$x = e^{2}$ $x=e^2$

Base- $e$ $e$ cancels out with the natural log ( $ln$ $ln$ ) function, so we can apply it to both sides. We get

$e^{ln x} = e^{2}$ $e^(lnx)=e^2$

$cancel(e)^(cancel(ln)x)=e^2$

Notice base- $e$ and $ln$ cancel, and we're left with

$x=e^2$

as our final answer.

Hope this helps!

Answer 2 · 2018-06-22T10:06:27

$color(green)(x = e^2 = 7.389$

$ln x = 2$

![http://slideplayer.com/slide/6865626/]( useruploads.socratic.org )

$color(green)(x = e^2 = 7.389$

How do you solve lnx=2lnx=2lnx=2?