How do you solve $lnx-ln(x+2)=1$ ?

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Answer 1 · 2016-03-19T12:44:48

$x=(2e)/(1-e)$

$ln x-ln(x+2)=1$

$ln (x/(x+2))=ln e" " "$ because $ln e=1$

$x/(x+2)=e$

$x=e(x+2)$

$x=ex+2e$

$x-ex=2e$

$x(1-e)=2e$

$(x(1-e))/((1-e))=(2e)/(1-e)$

$(xcancel((1-e)))/cancel((1-e))=(2e)/(1-e)$

$x=(2e)/(1-e)$

God bless...I hope the explanation is useful.

How do you solve lnx-ln(x+2)=1lnx-ln(x+2)=1?