How do you solve $lnx-ln2=0$ ?

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Answer 1 · 2017-08-25T12:57:17

$x=2$

$"using the "color(blue)"law of logarithms"$

$•color(white)(x)logx=logyrArrx=y$

$rArrlnx=ln2rArrx=2$

How do you solve lnx-ln2=0lnx-ln2=0?