Question

How do you solve `log (1/100) = log(10^(x+2))`?

Answer 1

`x=-4`

Explanation:

`"using the "color(blue)"law of logarithms"`

`•color(white)(x)logx=logyhArrx=y`

`1/100=10^(x+2)`

`10^(-2)=10^(x+2)`

`"since the bases are equal, equate the exponents"`

`x+2=-2rArrx=-4`