How do you solve ${log}_{10} x = - 2$ $Log_10x=-2$ ?

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Answer 1 · 2015-10-16T06:04:49

$x = \frac{1}{100}$ $x=1/100$

Using the rule ${log}_{a} M = N \Rightarrow M = a^{N}$ $log_a M=N rArr M= a^N$ ,

${log}_{10} x = - 2$ $log_10 x=-2$

$x = 10^{- 2}$ $x=10^-2$

$x = \frac{1}{10^{2}}$ $x=1/10^2$

$x = \frac{1}{100}$ $x=1/100$

How do you solve Log_10x=-2log10x=−2Log_10x=-2?