How do you solve ${log}_{10} x - 2 = 0$ $log_10x-2=0$ ?

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Answer 1 · 2017-01-21T23:21:48

Move to constant to right side
Make the logarithm disappear by making both sides an exponent of 10
Simplify the right

Given: ${log}_{10} (x) - 2 = 0$ $log_10(x) - 2 = 0$

Move the constant to the right:

${log}_{10} (x) = 2$ $log_10(x) = 2$

Make the logarithm disappear by making both sides the exponent of 10:

$10^{{log}_{10} (x)} = 10^{2}$ $10^(log_10(x)) = 10^2$

$x = 10^{2}$ $x = 10^2$

Simplify the right:

$x = 100$ $x = 100$

How do you solve log10x−2=0log_10x-2=0?