How do you solve $log_2(2x-3)=log_2(x+4)$ ?

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Answer 1 · 2017-02-13T15:52:14

$x = 7$ .

If $log_a b = log_a c$ , then $b = c$ .

$2x - 3= x +4$

$2x - x = 4 + 3$

$x = 7$

Hopefully this helps!

How do you solve log_2(2x-3)=log_2(x+4)log_2(2x-3)=log_2(x+4)?