Question

How do you solve `Log_2(x+2)-Log_2(x-2)=1`?

Answer 1

It is `x=6`

Explanation:

It is

#log_2(x+2)-log_2(x-2)=1=>log_2((x+2)/(x-2))=1=> (x+2)/(x-2)=2=>x+2=2*(x-2)=>x+2=2x-4=>x=6#