How do you solve $log (2 x - 1) = 3$ $Log(2x-1)=3$ ?

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Answer 1 · 2015-12-05T07:44:45

$x = \frac{1001}{2}$ $x=1001/2$

$log (2 x - 1) = 3 \to$ $log(2x-1)=3 ->$ generally log without base consider as common log so the base is 10

Write in exponential form
$2 x - 1 = 10^{3}$ $2x-1=10^3$

$2 x = 1001$ $2x=1001$
$x = \frac{1001}{2}$ $x=1001/2$

How do you solve Log(2x-1)=3log(2x−1)=3Log(2x-1)=3?