How do you solve log_2x=1/3log_2 27 ? Precalculus Solving Exponential and Logarithmic Equations Logarithmic Models 1 Answer Konstantinos Michailidis Jun 26, 2016 It is log_2x=1/3log_2 27=>log_2 x=1/3*(log27/log2)=> logx/log2=1/3*(3*log3/log2)=>logx=log3=>x=3 Answer link Related questions What is a logarithmic model? How do I use a logarithmic model to solve applications? What is the advantage of a logarithmic model? How does the Richter scale measure magnitude? What is the range of the Richter scale? How do you solve 9^(x-4)=81? How do you solve logx+log(x+15)=2? How do you solve the equation 2 log4(x + 7)-log4(16) = 2? How do you solve 2 log x^4 = 16? How do you solve 2+log_3(2x+5)-log_3x=4? See all questions in Logarithmic Models Impact of this question 1513 views around the world You can reuse this answer Creative Commons License